ScalingStacks

0PAI

Lemma 7.3.25. If ζ∈I⁡(ζ1,ζ2)\zeta\in I(\zeta_{1},\zeta_{2}), then supp⁡(ζ)⊂supp⁡(ζ1)∪supp⁡(ζ2)\operatorname{supp}\nolimits(\zeta)\subset\operatorname{supp}\nolimits(\zeta_{1})\cup\operatorname{supp}\nolimits(\zeta_{2}).

0PAJ

Proof. Consider three non-identity homotopy classes of paths ζ\zeta, ζ1\zeta_{1} and ζ2\zeta_{2} in 𝐑{\mathbf{R}} with ζ⁡(0)=ζ1​(0)≠ζ⁡(1)=ζ2​(0)\zeta(0)=\zeta_{1}(0)\neq\zeta(1)=\zeta_{2}(0). If ζ\zeta and ζ2∘ζ∘ζ1−1\zeta_{2}\circ\zeta\circ\zeta_{1}^{-1} have opposite orientations, then supp⁡(ζ)⊂supp⁡(ζ1)∪supp⁡(ζ2)\operatorname{supp}\nolimits(\zeta)\subset\operatorname{supp}\nolimits(\zeta_{1})\cup\operatorname{supp}\nolimits(\zeta_{2}). We deduce that the lemma holds for Z=S1Z=S^{1} by using the universal cover of ZZ. As a consequence, the lemma holds when ZZ is connected and smooth by embedding it in S1S^{1}, hence it holds for ZZ smooth. Lemma 7.3.24 shows that the lemma holds for any ZZ, since it holds for the non-singular cover of ZZ. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2