6.1.2. Twisted description
We describe now as a twisted free -module.
Consider with . Let be the permutation
such that and
the restrictions of to and to are increasing.
If , then we have a reduced decomposition
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and
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There is a bijection
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where is given by for and
for .
We have .
Given , we
define and as follows.
Let be minimal such that . We define
to be the cycle and
to be the cycle .
We have
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and .
Given , we define a free differential -module
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Given ,
we define
as the morphism of -modules given by
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We will show below (Lemma 6.1.3) that
.
We denote by the differential -module obtained as the corresponding
twisted object (cf §2.1.3).
We have as a -module and
.
0P79
Lemma 6.1.3. The maps define a twisted object .
There is an isomorphism of differential -modules
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0P7A
Proof. The length property of the bijection above shows that the map of the lemma
is an isomorphism of -modules.
Since
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it follows that the map of the lemma intertwines and the differential
of . The lemma follows.
∎
There is a dual version of Lemma 6.1.3. In particular, there is
a decomposition of right -modules
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