ScalingStacks

0PA0

Lemma 7.3.13. Let ζ\zeta be a homotopy class of paths in ZZ. The class f⁡(ζ)f(\zeta) is smooth if and only if ζ\zeta is smooth. If ζ\zeta is admissible, then f⁡(ζ)f(\zeta) is admissible.

0PA1

Proof. Given γ\gamma an oriented path in ZZ, the path f⁡(γ)f(\gamma) is oriented. It is smooth if and only f⁡(γ)f(\gamma) is smooth. This shows that if ζ\zeta is a smooth (resp. admissible) homotopy class of paths in ZZ, then f⁡(ζ)f(\zeta) is smooth (resp. admissible).

Consider now ζ\zeta a homotopy class of paths in ZZ such that f⁡(ζ)f(\zeta) is smooth. Given γ\gamma a minimal path in ζ\zeta, then f⁡(γ)f(\gamma) is minimal (Lemma 7.1.20). Since f⁡(ζ)f(\zeta) is smooth, it follows that f⁡(γ)f(\gamma) is smooth (Properties 7.3.5(4)), hence γ\gamma is smooth and finally ζ\zeta is smooth. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2