Lemma 7.1.21. Let be a path in such that has finitely many connected components, none of which contain or in the closure of their interior.
We have and for all .
Lemma 7.1.21. Let be a path in such that has finitely many connected components, none of which contain or in the closure of their interior.
We have and for all .
Proof. The first statement is clear. Let us now prove the second statement. That statement is clear if .
The left side of the equality is additive under compositions of paths, and so is the right side by Lemma 7.1.22 below.
Assume now is finite. The path is a (finite) composition of paths mapping into the complement of , hence the statement holds for .
Consider now the general case. The proof of Lemma 7.1.16 for produces a path homotopic to such that is finite and such that . Since the statement holds for , it follows that it holds for . ∎
Original source: arXiv:2009.09627v2