ScalingStacks

Let S′′S^{\prime\prime} be a subset of SS with nn elements, and let TT be a finite subset of MM. Let a:Hom𝒮∙​(Z)⁡(S′′,{ξ⁡(1),…​ξ​(n)})∧Hom𝒮∙​(Z)⁡(S∖S′′,T)→L∙​(T,S,en)a:\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S^{\prime\prime},\{\xi(1),\ldots\xi(n)\})\wedge\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S\setminus S^{\prime\prime},T)\to L^{\bullet}(T,S,e^{n}) be the map of Lemma 8.1.2. Let α∈Hom𝒮∙​(Z)⁡(S′′,{ξ⁡(1),…​ξ​(n)})\alpha\in\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S^{\prime\prime},\{\xi(1),\ldots\xi(n)\}) and β∈Hom𝒮∙​(Z)⁡(S∖S′′,T)\beta\in\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S\setminus S^{\prime\prime},T). Let θ=α⊠β=a⁡(α∧β)\theta=\alpha\boxtimes\beta=a(\alpha\wedge\beta). The statement (8.1.2) will follow from the following property:

(8.1.3) a⁡(d⁡(α⊗β))=d⁡(θ).a(d(\alpha\otimes\beta))=d(\theta).

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2