ScalingStacks

0PC6

Lemma 8.1.2. Given S⊂MS\subset M and n≥0n\geq 0, there is an isomorphism of functors 𝒮M∙​(Z)→Sets∙{\mathcal{S}}^{\bullet}_{M}(Z)\to\operatorname{Sets}\nolimits^{\bullet} (forgetting the differential)

⋁S′⊂S|S′|=nHom𝒮∙​(Z)⁡(S′,{ξ⁡(1),…,ξ⁡(n)})∧Hom𝒮∙​(Z)⁡(S∖S′,−)\displaystyle\bigvee_{\begin{subarray}{c}S^{\prime}\subset S\\ |S^{\prime}|=n\end{subarray}}\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S^{\prime},\{\xi(1),\ldots,\xi(n)\})\wedge\operatorname{Hom}\nolimits_{{\mathcal{S}}^{\bullet}(Z)}(S\setminus S^{\prime},-) →∼L∙​(−,S,en)\displaystyle\mathrel{\mathop{\kern 0.0pt\to}\limits^{\sim}}L^{\bullet}(-,S,e^{n})
(α,β)\displaystyle(\alpha,\beta) ↦α⊠β.\displaystyle\mapsto\alpha\boxtimes\beta.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2