0PD5 Proof. Let σ∈Bn\sigma\in B_{n} and r∈{1,…,n−1}r\in\{1,\ldots,n-1\}. Assume σTr≠0\sigma T_{r}\neq 0. If there is 1≤j≤i≤n1\leq j\leq i\leq n with σ(−i)=n−j+1\sigma(-i)=n-j+1 and i≠n+1−ri\neq n+1-r, then σTr∈Bn\sigma T_{r}\in B_{n}. Assume now σ(−i)∈T⊔(1,n−i)\sigma(-i)\in T\sqcup(1,n-i) for all i≠n+1−ri\neq n+1-r. We deduce that L(σ|{−(n+1−r),−(n−r)})≠∅L(\sigma_{|\{-(n+1-r),-(n-r)\}})\neq\emptyset, hence σTr=0\sigma T_{r}=0 (cf Lemma 8.2.4), a contradiction. Using Remark 8.2.6, we deduce that Trσ∈BnT_{r}\sigma\in B_{n}. The other assertions of the lemma are immediate. ∎