ScalingStacks

0P90

Proof. Consider γ\gamma and γ′\gamma^{\prime} two injective composable paths such that γ∘γ′\gamma\circ\gamma^{\prime} is injective. We have mc±​([γ​γ′])=mc±​([γ])+mc±​([γ′])m_{c}^{\pm}([\gamma\gamma^{\prime}])=m_{c}^{\pm}([\gamma])+m_{c}^{\pm}([\gamma^{\prime}]).

Consider now γ\gamma a minimal path. We have mc±​([γ])=mc∓​([γ−1])m_{c}^{\pm}([\gamma])=m_{c}^{\mp}([\gamma^{-1}]), hence mc​([γ])+mc​([γ−1])=0=mc​([γ−1∘γ])m_{c}([\gamma])+m_{c}([\gamma^{-1}])=0=m_{c}([\gamma^{-1}\circ\gamma]). The lemma follows. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2