ScalingStacks

0P4V

Proof. Let v∈Wv\in W. There is a unique decomposition v=v′​v′′v=v^{\prime}v^{\prime\prime} where ℓ⁡(v)=ℓ⁡(v′)+ℓ⁡(v′′)\ell(v)=\ell(v^{\prime})+\ell(v^{\prime\prime}), v′′∈WIv^{\prime\prime}\in W_{I} and v′∈WIv^{\prime}\in W^{I}.

We have d⁡(Tv)=d⁡(Tv′)​Tv′′+Tv′​d​(Tv′′)d(T_{v})=d(T_{v^{\prime}})T_{v^{\prime\prime}}+T_{v^{\prime}}d(T_{v^{\prime\prime}}). If u∈Wu\in W and u<v′u<v^{\prime}, then u∉wS​WIu{\not\in}w_{S}W_{I}. It follows that

tS,I​(d⁡(Tv))=tS,I​(Tv′​d​(Tv′′))=δv′,wI​d​(Tv′′)=d⁡(tS,I​(Tv)).t_{S,I}(d(T_{v}))=t_{S,I}(T_{v^{\prime}}d(T_{v^{\prime\prime}}))=\delta_{v^{\prime},w^{I}}d(T_{v^{\prime\prime}})=d(t_{S,I}(T_{v})).

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Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew Manion, Raphael Rouquier

Original source: arXiv:2009.09627v2