If \(g\) is \((n+1)\)-connected and \(gf\) is \(n\)-connected, then \(f\) is \(n\)-connected.
Original source: arXiv:2401.02956v2
Original source · 2401.02956v2
If \(g\) is \((n+1)\)-connected and \(gf\) is \(n\)-connected, then \(f\) is \(n\)-connected.
Original source: arXiv:2401.02956v2
Original source · 2401.02956v2