ScalingStacks

3.4.1 The \(\infty\)-category of chain complexes[0052]

Given an ordinary additive \(1\)-category \(\mathcal A\), the \(\infty\)-category \({\mathbf K}^b(\mathcal A)\) can be defined, see [Lur17, § 1.3.1], using the technology of dg nerves as follows.

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Definition 3.4.1. ([Lur17, Cons. 1.3.1.6 and Rem. 1.3.2.2]).

For an ordinary additive \(1\)-category \(\mathcal A\), we let \({\mathbf K}^b(\mathcal A):=N_{\mathrm{dg}}(\mathrm{Ch}^b(\mathcal A))\) denote the dg nerve of the dg category of bounded chain complexes in \(\mathcal A\).

Viewing \(\mathcal A\) as an additive \(\infty\)-category, there is a canonical additive functor \(\mathcal A\rightarrow{\mathbf K}^b(\mathcal A)\) induced from the functor that interprets objects of \(\mathcal A\) as chain complexes concentrated in degree zero.

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Proposition 3.4.2.

For an ordinary additive \(1\)-category \(\mathcal A\), the dg nerve \({\mathbf K}^b(\mathcal A)= N_{\mathrm{dg}}(\mathrm{Ch}^b(\mathcal A))\) is a stable \(\infty\)-category.

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Proof.

The dg nerve of the dg category of (unbounded) chain complexes is an \(\infty\)-category by [Lur17, Prop. 1.3.1.10] and stable by [Lur17, Prop. 1.3.2.10]. The full dg subcategory of bounded chain complexes is closed under shifts and formation of mapping cones, and thus its dg nerve \({\mathbf K}^b(\mathcal A)\) is itself a stable \(\infty\)-category, by [Lur17, Lem. 1.1.3.3] and the discussion after [Lur17, Proof of Prop. 1.3.2.10]. ◻

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Remark 3.4.3.

By [Lur17, Rem. 1.3.1.11], the homotopy 1-category \(h_1{\mathbf K}^b(\mathcal A)\), recalled in subsection A.2.1, is the chain homotopy category \(\mathrm{K}^b(\mathcal A)\) in the sense of definition 2.2.2. Note that, unlike the notion of derived category, which can only be defined for abelian categories, the stable \(\infty\)-category \({\mathbf K}^b(\mathcal A)\) is defined for any (possibly non-abelian) additive category \(\mathcal A\).

In corollary 3.4.10, we will prove that \({\mathbf K}^b(\mathcal A)\) is the universal stable \(\infty\)-category associated to \(\mathcal A\). To do so, we express \({\mathbf K}^b\) in terms of the functors constructed in the previous sections.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Yu Leon Liu, Aaron Mazel-Gee, David Reutter, Catharina Stroppel, Paul Wedrich

Original source: arXiv:2401.02956v2

Original source · 2401.02956v2