If \(\mathbb V\) is furthermore symmetric monoidal, then \(\mathrm{Fun}^{\mathcal K}_{\mathbb V}(\mathcal C, \mathcal D)\) admits a \(\mathbb V\)-action which makes it into a morphism object in \(\mathrm{Mod}_{\mathbb V}(\mathrm{Cat}_{\infty}^{\mathcal K})\).
Original source: arXiv:2401.02956v2
Original source · 2401.02956v2