ScalingStacks

0NP7

Proposition 9.5. Let 𝒜→ℬ→𝒞{\mathcal{A}}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}{\mathcal{B}}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}{\mathcal{C}} be an exact sequence of small stable ∞\infty-categories. Then the induced sequences

ℱκ​𝒜\textstyle{{\mathcal{F}}_{\kappa}{\mathcal{A}}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ℱκ​ℬ\textstyle{{\mathcal{F}}_{\kappa}{\mathcal{B}}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ℱκ​𝒞\textstyle{{\mathcal{F}}_{\kappa}{\mathcal{C}}}Σκ​𝒜\textstyle{\Sigma_{\kappa}{\mathcal{A}}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}Σκ​ℬ\textstyle{\Sigma_{\kappa}{\mathcal{B}}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}Σκ​𝒞\textstyle{\Sigma_{\kappa}{\mathcal{C}}}

are exact.

0NP8

Proof. It suffices to show the result for ℱκ{\mathcal{F}}_{\kappa}, as the statement for Σκ\Sigma_{\kappa} follows because colimits commute. Thus, we need to verify that

(Indω⁡(𝒜))κ⟶(Indω⁡(ℬ))κ⟶(Indω⁡(𝒞))κ(\Ind_{\omega}({\mathcal{A}}))^{\kappa}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}(\Ind_{\omega}({\mathcal{B}}))^{\kappa}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}(\Ind_{\omega}({\mathcal{C}}))^{\kappa}

is exact. The sequence

Indω⁡𝒜⟶Indω⁡ℬ⟶Indω⁡𝒞\Ind_{\omega}{\mathcal{A}}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}\Ind_{\omega}{\mathcal{B}}\mathchoice{\longrightarrow}{\rightarrow}{\rightarrow}{\rightarrow}\Ind_{\omega}{\mathcal{C}}

is exact by Definition 5.12 and Proposition 5.15. Now the result follows from Proposition 5.17. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Andrew J. Blumberg, David Gepner, Goncalo Tabuada

Original source: arXiv:1001.2282v4