[05UD] Proof. Let G:Δ[1]→W1G\colon\Delta[1]\rightarrow W_{1} denote the path connecting gg and g′g^{\prime}. Then it suffices to note that a dotted arrow exists in Δ[0]\displaystyle{{\Delta[0]}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}H\scriptstyle{H}W3\displaystyle{{W_{3}}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}Δ[1]\displaystyle{{\Delta[1]}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}(s0d1G,G,s0d0G)\scriptstyle{(s_{0}d_{1}G,G,s_{0}d_{0}G)}Maps𝒮(Z(3),W)\displaystyle{{\Map_{s{\operatorname{\mathcal{S}}}}(Z(3),W)}} where HH is a lift of (s0d1g′,g′,s0d0g′)=(idx′,g′,idy′)(s_{0}d_{1}g^{\prime},g^{\prime},s_{0}d_{0}g^{\prime})=(id_{x^{\prime}},g^{\prime},id_{y^{\prime}}) to W3W_{3}, since the right-hand vertical map is a fibration. ∎