where is the map corresponding to the word of
length , and where denotes the largest subobject of
not containing
.
We next note that can itself be decomposed. Thus let
denote the largest subobject of not
containing . If we let denote the inclusion of the “face” , then
we have that , and thus an isomorphism
(11.9)
Let be a simplicial space and a Segal space. Then each map
induces a map
of spaces. We introduce the following notation. Let
denote the subspace of
consisting of all simplices such that
for all . Then
is isomorphic to a union of some of the path
components of . In particular,
by definition,
and so .
Proof.The proof is by induction on . The case is immediate from
(11.6).
Now suppose the lemma is proved for the map
. From (11.9) we get a commutative
square
This square would be a pullback square if we left off the
“” decorations. Even with these decorations the square is
a pullback (and hence a homotopy pullback), as can be seen by
recalling that .
Thus by induction we see that the map
is a weak equivalence.
The proof now
follows from (11.11) and the fact
that the map
is a weak equivalence after restricting to the “”
components.
∎
Proof.Let denote the image of in
induced by the map . There is a square
of subobjects of ; we need to show that the inclusion map
of the union of these subobjects
is a weak equivalence in the Segal space model category structure.
Now can be written as a colimit of the poset of subcomplexes
each of which
(1)
are isomorphic to for some , and
(2)
include .
Straightforward calculation shows
that the intersection of with each of the
objects in the above diagram is a cover of .
∎
induced by an inclusion must factor through
, since each point of the mapping space
maps to a homotopy equivalence in the sense of
(5.5).
Let denote the map
associated to the inclusion classifying the point .
We have that
for
, and even when we have that
Then we must show that for each the fiber of over any point in the subspace
is contractible. The result
now follows from (11.10) applied to the pushout
diagrams (11.8).
∎