Lemma 3.9. If is a category, then is a Reedy fibrant simplicial space.
Proof. We must show that
is a fibration for each . We have the following cases:
- :
-
is a Kan complex by (3.2).
- :
-
is a simplicial covering space with discrete fiber, and thus is a fibration.
- :
-
is isomorphic to an inclusion of path-components, and so is a fibration.
- :
-
is an isomorphism, and thus a fibration.
∎
Original source: arXiv:math/9811037v3
Original source · math/9811037v3