ScalingStacks

0NYD

Proof. By Theorem 4.7, we know that ๐’ฏโ€‹rโ€‹(QCโก(X))\mathcal{T}r(\qc(X)), which is a tensor product, is also calculated by a fiber product

๐’ฏโ€‹rโ€‹(QCโก(X))โ‰ƒQCโก(Xร—Xร—XX).\mathcal{T}r(\qc(X))\simeq\qc(X\times_{X\times X}X).

On the other hand, by Corollary 4.10, we know that ๐’ตโก(QCโก(X))\mathcal{Z}(\qc(X)), which consists of functors, is also calculated by a tensor product

๐’ตโก(QCโก(X))โ‰ƒ๐’ฏโ€‹rโ€‹(QCโก(X)).\mathcal{Z}(\qc(X))\simeq\mathcal{T}r(\qc(X)).

โˆŽ

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

David Ben-Zvi, John Francis, David Nadler

Original source: arXiv:0805.0157v5