0NXI Proof. Let Σ0\Sigma_{0} be the 00-simplices of Σ\Sigma. Since XX has affine diagonal, the natural projection XΣ→XΣ0X^{\Sigma}\to X^{\Sigma_{0}} is affine. By Proposition 3.24, the product XΣ0X^{\Sigma_{0}} is perfect, and so by Proposition 3.21 (in the basic case of an affine morphism), the assertion follows. ∎