0N4C
Proof. After LemmaΒ 2.5, it will suffice to prove the result for the case , and so we omit from the notation and discussion.
The functor is a Cartesian fibration of -categories. Thus, to check finality, by Lemma 4.1.3.2 of [Lu1], it suffices to show that, for each , the fiber -category has contractible classifying space.
That is, we show that the -category , of -disks in equipped with an embedding , has a contractible classifying space.
There is an identification of spaces
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Formally, the sequence of maps
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is a fiber sequence (here the fiber is taken over any implicit morphism , thereby giving meaning to the lefthand space).
So we seek to show the map from the colimit
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is an equivalence of spaces.
We recognize this map of spaces as the map of fibers over of the map of right fibrations over :
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Being right fibrations, it is enough to show that this functor is an equivalence on maximal -subgroupoids.
Using LemmaΒ 2.12 which identifies these maximal -subgroupoids, this is the problem of showing, for each finite set , that the map of spaces
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is an equivalence.
LemmaΒ 2.19 implies the functor is final, and so the forgetful map
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is an equivalence of spaces.
Now notice that, for each , the map an open embedding. Also, for each point the image has cardinality at most . So there is an object of whose image contains the subset . We see then that the collection of open embeddings
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forms an open cover.
Because is a manifold, the collection of open embeddings from Euclidean spaces into form a basis for the topology of .
It follows that the collection of (at most) -tuples of disjoint open disks in forms an open cover of in such a way that any finite intersection of such is again covered by such.
This is to say that this collection of open embeddings forms a hypercover of .
Corollary 1.6 ofΒ [DI] gives that the map
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is an equivalence of spaces, which completes the proof.