ScalingStacks

[05Z9]

Lemma 5.1.2. Let π’ž\mathcal{C} and π’Ÿ\mathcal{D} be symmetric monoidal ∞\infty-categories and let F:π’žβ†’π’ŸF\colon\mathcal{C}\to\mathcal{D} be a symmetric monoidal functor. If FΒ―:π’žΒ―β†’π’ŸΒ―\underline{F}\colon\underline{\mathcal{C}}\to\underline{\mathcal{D}} is a left adjoint, then the induced functor FβŠ—:π’žβŠ—β†’π’ŸβŠ—F^{\otimes}\colon\mathcal{C}^{\otimes}\to\mathcal{D}^{\otimes} is a left adjoint relative to π…π’π§βˆ—\mathbf{Fin}_{*} and for every ∞\infty-operad 𝒫\mathcal{P} the induced functor Alg¯𝒫​(π’ž)β†’Alg¯𝒫​(π’Ÿ)\underline{\operatorname{Alg}}_{\mathcal{P}}\left(\mathcal{C}\right)\to\underline{\operatorname{Alg}}_{\mathcal{P}}\left(\mathcal{D}\right) is a left adjoint.

[05ZA]

Proof. For every ⟨nβŸ©βˆˆπ…π’π§βˆ—\left\langle n\right\rangle\in\mathbf{Fin}_{*}, the restriction of FβŠ—F^{\otimes} to the fiber over ⟨n⟩\left\langle n\right\rangle is just Fn:π’žnβ†’π’ŸnF^{n}\colon\mathcal{C}^{n}\to\mathcal{D}^{n}, which is clearly a left adjoint. Hence, by A.7.3.2.7, the functor FβŠ—F^{\otimes} is a left adjoint relative to π…π’π§βˆ—\mathbf{Fin}_{*}. Let GβŠ—G^{\otimes} be the right adjoint of FβŠ—.F^{\otimes}. Applying A.7.3.2.13, we obtain that FβŠ—F^{\otimes} and GβŠ—G^{\otimes} induce an adjunction:

Alg¯𝒫​(π’ž)⇆Alg¯𝒫​(π’Ÿ).\underline{\operatorname{Alg}}_{\mathcal{P}}\left(\mathcal{C}\right)\leftrightarrows\underline{\operatorname{Alg}}_{\mathcal{P}}\left(\mathcal{D}\right).

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Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Tomer Schlank, Lior Yanovski

Original source: arXiv:1808.06006v3

Original source page 35

Original source Β· 1808.06006v3