ScalingStacks

[05YR]

Proof. By the Yoneda lemma it is enough to show that for every nn-truncated object ZZ in 𝒞\mathcal{C} the induced map

f∗:Map⁡(B,Z)→Map⁡(A,Z)f_{*}\colon\operatorname{Map}\left(B,Z\right)\to\operatorname{Map}\left(A,Z\right)

is an equivalence. For this, it is enough to show that for every g:A→Zg\colon A\to Z, the fiber of f∗f_{*} over gg is contractible. By T.5.5.5.12, the fiber is equivalent to the space of lifts for the square

A\textstyle{A\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}Z\textstyle{Z\ignorespaces\ignorespaces\ignorespaces\ignorespaces}B\textstyle{B\ignorespaces\ignorespaces\ignorespaces\ignorespaces}pt,\textstyle{\text{pt},}

which is contractible by definition as f:A→Bf\colon A\to B was assumed to be nn-connected. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Tomer Schlank, Lior Yanovski

Original source: arXiv:1808.06006v3

    Original source page 31

    Original source · 1808.06006v3