ScalingStacks

[05WT]

Proof. Let p:ℳ→Δ1p\colon\mathcal{M}\to\Delta^{1} be the coCartesian fibration associated with the functor LL (which is also Cartesian, since LL has a right adjoint). We can assume that we have a commutative diagram

Δ1×𝒞\textstyle{\Delta^{1}\times\mathcal{C}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}s\scriptstyle{s}ℳ\textstyle{\mathcal{M}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}p\scriptstyle{p}Δ1,\textstyle{\Delta^{1},}

such that s|Δ{0}×𝒞=Ids|_{\Delta^{\left\{0\right\}}\times\mathcal{C}}=\operatorname{Id}, s|Δ{1}×𝒞=Ls|_{\Delta^{\left\{1\right\}}\times\mathcal{C}}=L and s|Δ1×{X}s|_{\Delta^{1}\times\left\{X\right\}} is a coCartesian edge of ℳ\mathcal{M} for every X∈𝒞X\in\mathcal{C} (combine T.5.2.1.1 and T.5.2.1.3). It is clear from T.1.2.9.2 that for any pair of ∞\infty-categories with objects X∈𝒞X\in\mathcal{C} and Y∈𝒟Y\in\mathcal{D} there is a canonical isomorphism

(𝒞×𝒟)(X,Y)/≃𝒞X/×𝒟Y/.\left(\mathcal{C}\times\mathcal{D}\right)_{\left(X,Y\right)/}\simeq\mathcal{C}_{X/}\times\mathcal{D}_{Y/}.

Hence, we get an induced commutative diagram

Δ1×𝒞X/≃(Δ1×𝒞)(0,X)/\textstyle{\Delta^{1}\times\mathcal{C}_{X/}\simeq\left(\Delta^{1}\times\mathcal{C}\right)_{\left(0,X\right)/}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}s\scriptstyle{s}ℳX/\textstyle{\mathcal{M}_{X/}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}pX\scriptstyle{p_{X}}Δ1≃Δ0/1.\textstyle{\Delta^{1}\simeq\Delta_{0/}^{1}.}

The functor pXp_{X} is a Cartesian and coCartesian fibration by the duals of T.2.4.3.1(1) and T.2.4.3.2(1). Moreover, an edge in ℳX/\mathcal{M}_{X/} is (co)Cartesian if and only if its projection to ℳ\mathcal{M} is (co)Cartesian by the duals of T.2.4.3.1(2) and T.2.4.3.2(2), which shows that the functor LXL_{X} is associated with pXp_{X}. It follows that LXL_{X} has a right adjoint RXR_{X}.

Assuming that RR is fully faithful, we will show that RXR_{X} is fully faithful by showing that the counit of the adjunction LX⊣RXL_{X}\dashv R_{X} is an equivalence. For every object, the counit map is an edge of ℳX/\mathcal{M}_{X/}. Since the projection ℳX/→ℳ\mathcal{M}_{X/}\to\mathcal{M} is conservative, it is enough to show that the counit map of LX⊣RXL_{X}\dashv R_{X} is mapped to the counit map of L⊣RL\dashv R. Indeed, for an object Y∈𝒟≃ℳ|Δ{1}Y\in\mathcal{D}\simeq\mathcal{M}|_{\Delta^{\left\{1\right\}}}, we choose a Cartesian edge e:R⁡(Y)→Ye\colon R\left(Y\right)\to Y and a coCartesian edge d:R⁡(Y)→L⁡(R⁡(Y))d\colon R\left(Y\right)\to L\left(R\left(Y\right)\right), and combine them into a commutative diagram of the form:

Λ02\textstyle{\Lambda_{0}^{2}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}f\scriptstyle{f}ℳ\textstyle{\mathcal{M}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}p\scriptstyle{p}Δ2\textstyle{\Delta^{2}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}Δ1,\textstyle{\Delta^{1},}

where f|Δ{0,1}=df|_{\Delta^{\left\{0,1\right\}}}=d and f|Δ{0,2}=ef|_{\Delta^{\left\{0,2\right\}}}=e. Since dd is coCartesian, there exists a lift f¯:Δ2→ℳ\overline{f}\colon\Delta^{2}\to\mathcal{M} that gives an edge

f¯|Δ{1,2}=c:L⁡(R⁡(Y))→Y\overline{f}|_{\Delta^{\left\{1,2\right\}}}=c\colon L\left(R\left(Y\right)\right)\to Y

that is isomorphic to the counit map of the adjunction L⊣RL\dashv R at YY in the homotopy category h​𝒟h\mathcal{D}. We can similarly construct the counit map for an object of ℳX/\mathcal{M}_{X/}. The assertion now follows from the above characterization of (co)Cartesian edges in ℳX/\mathcal{M}_{X/}. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Tomer Schlank, Lior Yanovski

Original source: arXiv:1808.06006v3

    Original source page 8

    Original source · 1808.06006v3