Example 5.6. If is a standard 4-ball with , then the evaluation of lasagna fillings induces an isomorphism . In other words, the above complicated quotient yields the usual in this case.
Proof. It follows from Theorem 5.2 that equivalent lasagna fillings of have equal evaluation. Thus, we get a well-defined homomorphism , which is surjective since any homogeneous appears as the image of a radial lasagna filling . Similarly, if two lasagna fillings and have equal evaluation , then we observe , and so is injective. ∎
Original source: arXiv:1907.12194v5