ScalingStacks

Observation 2.6. Because $\mathbb{R}^{n}$ is connected, this tangent classifier $\tau\colon\mfld_{n}\to\spaces_{/\BTop(n)}$ is symmetric monoidal with respect to coproducts in the codomain. In other words, $\tau$ carries finite disjoint unions to finite coproducts over $\BTop(n)$.