ScalingStacks

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Lemma 3.1. Let k=𝔽qk=\mathbb{F}_{q} or k=𝔽¯pk=\overline{\mathbb{F}}_{p}, then

HomDM⁡(k,ℚ)⁡(ℚ,ℚ⁡(m)​[n])={ℚ for ​n=m=0​ and0otherwise.\displaystyle\operatorname{Hom}_{\operatorname{DM}(k,\mathbb{Q})}(\mathbb{Q},\mathbb{Q}(m)[n])=\left\{\begin{array}[]{cl}\mathbb{Q}&\text{ for }n=m=0\text{ and}\\ 0&\text{otherwise.}\\ \end{array}\right.
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Proof. First, note that the higher KK-theory of finite fields Ki​(Spec⁡(𝔽q))K_{i}(\operatorname{Spec}(\mathbb{F}_{q})) is torsion for i>0i>0 by [Qui72, Theorem 8]. The same is true for the algebraic closure, since KK-theory commutes with filtered colimits. Hence, Ki​(k)ℚ=0K_{i}(k)_{\mathbb{Q}}=0 for i>0.i>0. By the Riemann–Roch theorem for rational higher Chow groups, see [Blo86, Theorem 9.1], CHm⁡(k,2​m−n)ℚ\operatorname{CH}^{m}(k,2m-n)_{\mathbb{Q}} is a direct summand of K2​m−n​(k)ℚ.K_{2m-n}(k)_{\mathbb{Q}}. The statement follows from (3.2). ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Jens Niklas Eberhardt, Catharina Stroppel

Original source: arXiv:2109.00305v2