ScalingStacks

Let us consider two four-manifolds WW and ZZ that have some part YY of their boundaries in common, as follows:

∂W=Y∐Y0,∂Z=(−Y)∐Y1,\partial W=Y\amalg Y_{0},\ \ \partial Z=(-Y)\amalg Y_{1},

where ∐\amalg denotes disjoint union. We can glue WW and ZZ along YY to form a new four-manifold W∪ZW\cup Z with boundary Y0∐Y1Y_{0}\amalg Y_{1}. Suppose we are also given links L0⊂Y0L_{0}\subset Y_{0}, L1⊂Y1L_{1}\subset Y_{1} and L⊂YL\subset Y. Let L¯⊂−Y\overline{L}\subset-Y denote the mirror reverse of LL. Then, we have a map

(3) Ψ:𝒮0N​(W,L∪L0)⊗𝒮0N​(Z,L¯∪L1)→𝒮0N​(W∪Z,L0∪L1)\Psi:\mathcal{S}_{0}^{N}(W;L\cup L_{0})\otimes\mathcal{S}_{0}^{N}(Z;\overline{L}\cup L_{1})\to\mathcal{S}_{0}^{N}(W\cup Z;L_{0}\cup L_{1})

obtained by gluing lasagna fillings along LL:

[F]⊗[G]↦[F∪G].[F]\otimes[G]\mapsto[F\cup G].

It is easy to see that if two lasagna fillings F1F_{1} and F2F_{2} are equivalent in WW, and G1G_{1} and G2G_{2} are equivalent in ZZ, then F1∪G1F_{1}\cup G_{1} and F2∪G2F_{2}\cup G_{2} are equivalent in W∪ZW\cup Z, so (3) is well-defined.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Ciprian Manolescu, Kevin Walker, Paul Wedrich

Original source: arXiv:2206.04616v2