ScalingStacks

2.1. Skein lasagna modules

We start by reviewing the construction of skein lasagna modules from [27, Section 5.2].

Following [27] and [25], for a framed link L⊂ℝ3L\subset{\mathbb{R}}^{3}, we write

KhRN⁡(L)=⨁i,j∈ℤKhRNi,j⁡(L)\operatorname{KhR}_{N}(L)=\bigoplus_{i,j\in{\mathbb{Z}}}\operatorname{KhR}_{N}^{i,j}(L)

for the 𝔤​𝔩N\mathfrak{gl}_{N} version of Khovanov-Rozansky homology. Here, ii denotes the homological grading and jj denotes the quantum grading.

If we have an oriented manifold SS diffeomorphic to the standard 33-sphere S3S^{3}, and a framed link L⊂SL\subset S, we can define a canonical invariant KhRN⁡(S,L)\operatorname{KhR}_{N}(S,L) as in [27, Definition 4.12]. We sometimes drop SS from the notation and simply write KhRN⁡(L)\operatorname{KhR}_{N}(L).

Given a framed cobordism Σ⊂S3×[0,1]\Sigma\subset S^{3}\times[0,1] from L0L_{0} to L1L_{1}, there is an induced map

KhRN⁡(Σ):KhRN⁡(L0)→KhRN⁡(L1)\operatorname{KhR}_{N}(\Sigma)\colon\operatorname{KhR}_{N}(L_{0})\to\operatorname{KhR}_{N}(L_{1})

which is homogeneous of bidegree (0,(1−N)​χ​(Σ))(0,(1-N)\chi(\Sigma)).

Let WW be a four-manifold and L⊂∂WL\subset\partial W a framed link. A lasagna filling F=(Σ,{(Bi,Li,vi)})F=(\Sigma,\{(B_{i},L_{i},v_{i})\}) of WW with boundary LL consists of

  • •

    A finite collection of disjoint 44-balls BiB_{i} (called input balls) embedded in the interior or WW;

  • •

    A framed oriented surface Σ\Sigma properly embedded in W∖∪iBiW\setminus\cup_{i}B_{i}, meeting ∂W\partial W in LL and meeting each ∂Bi\partial B_{i} in a link LiL_{i}; and

  • •

    for each ii, a homogeneous label vi∈KhRN⁡(∂Bi,Li).v_{i}\in\operatorname{KhR}_{N}(\partial B_{i},L_{i}).

The bidegree of a lasagna filling FF is

deg⁡(F):=∑ideg⁡(vi)+(0,(1−N)​χ​(Σ)).\deg(F):=\sum_{i}\deg(v_{i})+(0,(1-N)\chi(\Sigma)).

If WW is a 44-ball, we can define a cobordism map

KhRN⁡(Σ):⨂iKhRN⁡(∂Bi,Li)→KhRN⁡(∂W,L)\operatorname{KhR}_{N}(\Sigma)\colon\bigotimes_{i}\operatorname{KhR}_{N}(\partial B_{i},L_{i})\to\operatorname{KhR}_{N}(\partial W,L)

and an evaluation

KhRN(F):=KhRN(Σ)(⊗ivi)∈Kh(∂W,L).\operatorname{KhR}_{N}(F):=\operatorname{KhR}_{N}(\Sigma)(\otimes_{i}v_{i})\in\operatorname{Kh}(\partial W,L).

We define the skein lasagna module as the bigraded abelian group

𝒮0N(W;L):=ℤ{lasagna fillings F of W with boundary L}/∼\mathcal{S}_{0}^{N}(W;L):={\mathbb{Z}}\{\text{lasagna fillings $F$ of $W$ with boundary $L$}\}/\sim

where ∼\sim is the transitive and linear closure of the following relation:

  1. (a)

    Linear combinations of lasagna fillings are set to be multilinear in the labels viv_{i};

  2. (b)

    Furthermore, two lasagna fillings F1F_{1} and F2F_{2} are set to be equivalent if F1F_{1} has an input ball BiB_{i} with label viv_{i}, and F2F_{2} is obtained from F1F_{1} by replacing BiB_{i} with another lasagna filling F3F_{3} of a 44-ball such that vi=KhRN⁡(F3)v_{i}=\operatorname{KhR}_{N}(F_{3}), followed by an isotopy rel ∂W\partial W (where the isotopy is allowed to move the input balls):

    v k ∼ B i B j F 3 B i B j F 2 F 1 v i v j v j v l

For future reference, here is a useful lemma.

0NFP

Lemma 2.1. Let WW and LL be as above, and fix balls R1,…,RnR_{1},\dots,R_{n}, one in each connected component of WW. Then, the equivalence relation defining 𝒮0N​(W,L)\mathcal{S}_{0}^{N}(W;L) can be alternatively be described as the transitive and linear closure of the following relation:

  • •

    Linear combinations of lasagna fillings are set to be multilinear in the labels viv_{i};

  • •

    Lasagna fillings that are isotopic rel ∂W\partial W are set to be equivalent;

  • •

    Two lasagna fillings are also set to be equivalent if they differ as in (b) above, where the input ball BiB_{i} is one of the chosen balls R1,…,RnR_{1},\dots,R_{n}.

0NFQ

Proof. If F1F_{1} and F2F_{2} are equivalent as in the lemma, let us show that they are equivalent as in the definition of the skein lasagna module. The only new relation is the isotopy, which can be thought of as a particular instance of (b), where B1B_{1} is replaced by a slightly smaller ball with the same decoration (and F3F_{3} is a product cobordism).

Conversely, if F1F_{1} and F2F_{2} are equivalent as in the definition of the skein lasagna module, we only have to consider the case when they are related by (b). We can then isotope BiB_{i} to turn it into the ball RjR_{j} in the same connected component, and view (b) as a combination of the moves in the lemma. ∎

Skein lasagna modules decompose according to relative homology classes, as noted in [25, Section 2.3]:

(1) 𝒮0N​(W,L)=⨁α∈H2​(W,L,ℤ)𝒮0N​(W,L,α).\displaystyle\mathcal{S}_{0}^{N}(W;L)=\bigoplus\limits_{\alpha\in H_{2}(W,L;{\mathbb{Z}})}\mathcal{S}_{0}^{N}(W;L,\alpha).

Observe that in the case where LL is not null-homologous in WW (i.e. [L]≠0∈H1​(W,ℤ)[L]\neq 0\in H_{1}(W;{\mathbb{Z}})), then there are no lasagna fillings, so 𝒮0N​(W,L)=0\mathcal{S}_{0}^{N}(W;L)=0. When [L]=0∈H1​(W,ℤ)[L]=0\in H_{1}(W;{\mathbb{Z}}), consider the boundary map in the long exact sequence of the pair (W,L)(W,L):

∂:H2​(W,L,ℤ)→H1​(L,ℤ).\partial:H_{2}(W,L;{\mathbb{Z}})\to H_{1}(L;{\mathbb{Z}}).

The only classes α∈H2​(W,L,ℤ)\alpha\in H_{2}(W,L;{\mathbb{Z}}) that can contribute non-trivially are those that map to the fundamental class [L]∈H1​(L,ℤ)[L]\in H_{1}(L;{\mathbb{Z}}) under ∂\partial. Let us introduce the notation

H2L​(W,ℤ):=∂−1([L])⊆H2​(W,L,ℤ).H_{2}^{L}(W;{\mathbb{Z}}):=\partial^{-1}([L])\subseteq H_{2}(W,L;{\mathbb{Z}}).

Note that, using the long exact sequence of the pair, the difference of two classes in H2L​(W,ℤ)H_{2}^{L}(W;{\mathbb{Z}}) can be identified with an element of H2​(W,ℤ)H_{2}(W;{\mathbb{Z}}). Thus, H2L​(W,ℤ)H_{2}^{L}(W;{\mathbb{Z}}) is a torsor over H2​(W,ℤ)H_{2}(W;{\mathbb{Z}}); it can be identified with the latter group after choosing a base element in H2L​(W,ℤ)H_{2}^{L}(W;{\mathbb{Z}}).

The decomposition  (1) becomes

(2) 𝒮0N​(W,L)=⨁α∈H2L​(W,ℤ)𝒮0N​(W,L,α).\displaystyle\mathcal{S}_{0}^{N}(W;L)=\bigoplus\limits_{\alpha\in H_{2}^{L}(W;{\mathbb{Z}})}\mathcal{S}_{0}^{N}(W;L,\alpha).

We will use the decomposition (2) in the case of a general link LL; when [L]≠0[L]\neq 0, we have H2L​(W,ℤ)=∅H_{2}^{L}(W;{\mathbb{Z}})=\emptyset and 𝒮0N​(W,L)=0\mathcal{S}_{0}^{N}(W;L)=0.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Ciprian Manolescu, Kevin Walker, Paul Wedrich

Original source: arXiv:2206.04616v2