Proof. If and are equivalent as in the lemma, let us show that they are equivalent as in the definition of the skein lasagna module. The only new relation is the isotopy, which can be thought of as a particular instance of (b), where is replaced by a slightly smaller ball with the same decoration (and is a product cobordism).
Conversely, if and are equivalent as in the definition of the skein lasagna module, we only have to consider the case when they are related by (b). We can then isotope to turn it into the ball in the same connected component, and view (b) as a combination of the moves in the lemma. ∎