ScalingStacks

0NFQ

Proof. If F1F_{1} and F2F_{2} are equivalent as in the lemma, let us show that they are equivalent as in the definition of the skein lasagna module. The only new relation is the isotopy, which can be thought of as a particular instance of (b), where B1B_{1} is replaced by a slightly smaller ball with the same decoration (and F3F_{3} is a product cobordism).

Conversely, if F1F_{1} and F2F_{2} are equivalent as in the definition of the skein lasagna module, we only have to consider the case when they are related by (b). We can then isotope BiB_{i} to turn it into the ball RjR_{j} in the same connected component, and view (b) as a combination of the moves in the lemma. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Ciprian Manolescu, Kevin Walker, Paul Wedrich

Original source: arXiv:2206.04616v2