Theorem 4.7.Let with a nullhomologous link in the boundary that intersects the belt spheres of the 1-handles
transversely in points for . Let denote the tangle obtained
from by cutting open along the belt spheres. Then we have an isomorphism:
where the relation is given by taking coinvariants for the actions of
, i.e. by identifying the images of the actions
for all pairs of tangles , with boundary .
(Here we have omitted a global grading shift.)
Proof.The map is defined by first considering the direct sum of the gluing morphisms
from
(17). The coinvariants for the actions of
clearly lie in the kernel, so we get an induced map from the indicated
quotient to , which we again call the gluing map. It is
surjective by Lemma 4.4, so it remains to prove injectivity.
Let
be two equivalent linear combinations of lasagna fillings in
, and let be respective preimages under the gluing map. We want
to show that and are equivalent. Without loss of generality, we
may assume that and are individual lasagna fillings (rather than
linear combinations) and that they differ by a single move as in
Lemma 2.1 with the relevant input ball fixed and disjoint
from the cocores of the 1-handles in . If and differ by a
replacement inside the fixed input ball or an isotopy supported away from
the cocores, then and are equal in . If and differ by an isotopy supported
in a neighborhood of the cocores, then or differ by an element
of the subspace factored out. Since every isotopy of lasagna fillings can be
factored in this way, we get that and are equivalent.
∎