ScalingStacks

[0MKN]

Remark 13.12. We note that the construction of a 𝒬\mathcal{Q}, AA, and BB demonstrably satisfying the above properties appears to be somewhat delicate. In the case i=0i=0 the original published proof [34, Proposition 6.6] was incorrect, and a corrected proof has been supplied by Rezk in [35, Proposition 2.1].

It is possible to give an alternative proof of Lemma 13.11 which builds directly on Rezk’s proof in the case i=0i=0. Let 𝒬\mathcal{Q} be Rezk’s category 𝒬m,n\mathcal{Q}_{m,n} as defined in [35], and following Rezk define functors A(i=0)A^{(i=0)} and B(i=0)B^{(i=0)} as the objects

Aδ(i=0)\displaystyle A^{(i=0)}_{\delta} :=V(δ1,δ2)−1​(M×N)​(D1,…,Dp),and\displaystyle:=V_{(\delta_{1},\delta_{2})^{-1}(M\times N)}(D_{1},\dots,D_{p}),\quad\text{and}
Bδ(i=0)\displaystyle B^{(i=0)}_{\delta} :=V⁡[p]​(D1,…,Dp),\displaystyle:=V[p](D_{1},\dots,D_{p}),

where we are also using the notation of [35]. Then these choices satisfy the requisite properties for the case i=0i=0, the most difficult being [35, Proposition 2.3].

For general ii, notice that we have inclusions of subobjects

V×CiH\displaystyle V\times_{C_{i}}H ⊆V×H,\displaystyle\subseteq V\times H,
U×CiH\displaystyle U\times_{C_{i}}H ⊆U×H.\displaystyle\subseteq U\times H.

We may define AδA_{\delta} and BδB_{\delta} as pullbacks

Aδ\displaystyle A_{\delta} =Aδ(i=0)×(U×H)(U×CiH), and\displaystyle=A^{(i=0)}_{\delta}\times_{(U\times H)}(U\times_{C_{i}}H),\text{ and}
Bδ\displaystyle B_{\delta} =Bδ(i=0)×(V×H)(V×CiH).\displaystyle=B^{(i=0)}_{\delta}\times_{(V\times H)}(V\times_{C_{i}}H).

Since colimits in ∞\infty-topoi are universal we have

colim𝒬A\displaystyle\colim_{\mathcal{Q}}A ≃colim𝒬A(i=0)×(U×H)(U×CiH)≃U×CiH,\displaystyle\simeq\colim_{\mathcal{Q}}A^{(i=0)}\times_{(U\times H)}(U\times_{C_{i}}H)\simeq U\times_{C_{i}}H,
colim𝒬B\displaystyle\colim_{\mathcal{Q}}B ≃colim𝒬B(i=0)×(V×H)(V×CiH)≃V×CiH,\displaystyle\simeq\colim_{\mathcal{Q}}B^{(i=0)}\times_{(V\times H)}(V\times_{C_{i}}H)\simeq V\times_{C_{i}}H,

and so all that remains is to verify that Aδ→BδA_{\delta}\to B_{\delta} is indeed in TΘnT_{\Theta_{n}}. This can be accomplished by explicitly computing AδA_{\delta} and BδB_{\delta} in terms of the functors σ[ℓ]!\sigma^{[\ell]}_{!} and invoking Lemma 13.5.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Clark Barwick, Christopher Schommer-Pries

Original source: arXiv:1112.0040v6

Original source · 1112.0040v6