ScalingStacks

[0MJV]

Lemma 11.4. Condition (R.1) is implied by the conjunction of the following.

  1.   (R.1-bis(a))

    i∗​(S00)⊂Ti^{*}(S_{00})\subset T.

  2.   (R.1-bis(b))

    For any morphism U′→V′U^{\prime}\to V^{\prime} of T0T_{0}, and for any morphisms V′→i∗​(Ci)V^{\prime}\to i^{*}(C_{i}) and H→CiH\to C_{i} with H∈ΥnH\in\Upsilon_{n}, the pullback

    U′×i∗​(Ci)i∗​H→V′×i∗​Cii∗​HU^{\prime}\times_{i^{*}(C_{i})}i^{*}H\to V^{\prime}\times_{i^{*}C_{i}}i^{*}H

    lies in TT.

[0MJW]

Proof. First, consider the subclass T′⊂TT^{\prime}\subset T containing those morphisms U′→V′U^{\prime}\to V^{\prime} of TT such that for any nondegenerate morphisms V′→CkV^{\prime}\to C_{k} and H→CkH\to C_{k}, the pullback

U′×CkH→V′×CkHU^{\prime}\times_{C_{k}}H\to V^{\prime}\times_{C_{k}}H

lies in TT. Since colimits in 𝒫⁡(ℛ)\pre(\mathcal{R}) are universal, one deduces immediately that the class T′T^{\prime} is strongly saturated. Hence (R.1-bis(b)) implies that T′=TT^{\prime}=T. Thus TT is closed under pullbacks along morphisms H→CkH\to C_{k} and contains i∗​S00i^{*}S_{00} (by (R.1-bis(a))), hence contains all of i∗​S0i^{*}S_{0}. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

Clark Barwick, Christopher Schommer-Pries

Original source: arXiv:1112.0040v6

Original source · 1112.0040v6