Proof (of 2.13). For this follows directly from the definitions, and so we assume that . Let be a simplicial set. On the one hand,
|
|
|
|
|
|
|
|
|
|
where subscript indicates that we take only
the subset of maps that restrict to on
(observe that this is independent of the representative as ).
On the other hand,
|
|
|
|
|
We will argue that this last set is in natural bijection with the
set
|
|
|
First, by definition of the right mapping space we have a natural
bijection between maps of the form and maps of the form
restricting
to on .
Second, extends to if and only if extends
to . Likewise, it is clear that two maps
agree on if and only if the corresponding maps
agree on . Hence, the only thing we
need to show is that and are homotopic rel. if
and only if and are homotopic rel.
and this follows from in 2.17.
It remains to observe that for every simplicial set and every we have a canonical
isomorphism Hence,
we get a natural bijection
|
|
|
and therefore an isomorphism .
Finally, we need to show that the isomorphism we have constructed is compatible with
the maps and
.
For this, consider a map .
The composition is represented by the restriction ,
which corresponds to the map .
On the other hand, the composition corresponds to
the restriction of to
and these are identified by .
โ