ScalingStacks

3.3. The Braiding

(∙⊗∙)(\bullet\otimes\bullet): For any two objects we have the morphism

(RA,B,RRA,B,−):(A⊗B,RA,−⊗RB,−,R~A⊗R~B)→(B⊗A,RB,−⊗RA,−,R~B⊗R~A)(R_{A,B},R_{R_{A,B},-}):(A\otimes B,R_{A,-}\otimes R_{B,-},\tilde{R}_{A}\otimes\tilde{R}_{B})\to(B\otimes A,R_{B,-}\otimes R_{A,-},\tilde{R}_{B}\otimes\tilde{R}_{A})

in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}), where the 2-morphism RRA,B,XR_{R_{A,B},X} is defined to be the pasting:

A​B​X{\lx@inpgf@ignorespaces ABX}B​A​X{\lx@inpgf@ignorespaces BAX}A​X​B{\lx@inpgf@ignorespaces AXB}B​X​A{\lx@inpgf@ignorespaces BXA}X​A​B{\lx@inpgf@ignorespaces XAB}X​B​A{\lx@inpgf@ignorespaces XBA}RA,B⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A,B}\otimes X}A⊗RB,X\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,X}}B⊗RA,X\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{A,X}}⇓R~(A|B,X){\lx@inpgf@ignorespaces\Downarrow\tilde{R}_{(A|B,X)}}⇓RA,RB,X−1{\lx@inpgf@ignorespaces\Downarrow R_{A,R_{B,X}}^{-1}}⇓R~(A|X,B)−1{\lx@inpgf@ignorespaces\Downarrow\tilde{R}_{(A|X,B)}^{-1}}RA,X⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes B}RB,X⊗A\scriptstyle{\lx@inpgf@ignorespaces R_{B,X}\otimes A}X⊗RA,B\scriptstyle{\lx@inpgf@ignorespaces X\otimes R_{A,B}}

First we have to show that RRA,B,−R_{R_{A,B},-} satisfies (→⊗→)({\to}\otimes{\to}) and hence is a modification. This is shown in the following diagram (or follows from the fact that it is a pasting of modifications).

A​B​X{\lx@inpgf@ignorespaces ABX}    B​A​X{\lx@inpgf@ignorespaces BAX}A​B​X′{\lx@inpgf@ignorespaces ABX^{\prime}}B​A​X′{\lx@inpgf@ignorespaces BAX^{\prime}}A​X​B{\lx@inpgf@ignorespaces AXB}B​X​A{\lx@inpgf@ignorespaces BXA}A​X′​B{\lx@inpgf@ignorespaces AX^{\prime}B}B​X′​A{\lx@inpgf@ignorespaces BX^{\prime}A}X​A​B{\lx@inpgf@ignorespaces XAB}X​B​A{\lx@inpgf@ignorespaces XBA}X′​A​B{\lx@inpgf@ignorespaces X^{\prime}AB}X′​B​A{\lx@inpgf@ignorespaces X^{\prime}BA}A⊗RB,X\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,X}}RA,B⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A,B}\otimes X}B​A⊗f\scriptstyle{\lx@inpgf@ignorespaces BA\otimes f}RA,B⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A,B}\otimes X}B⊗RA,X′\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{A,X^{\prime}}}RA,X⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes B}RB,X′⊗A\scriptstyle{\lx@inpgf@ignorespaces R_{B,X^{\prime}}\otimes A}f⊗A​B\scriptstyle{\lx@inpgf@ignorespaces f\otimes AB}X′⊗RA,B\scriptstyle{\lx@inpgf@ignorespaces X^{\prime}\otimes R_{A,B}}

The front and the back side of the cube are the 2-morphisms RRA,B,XR_{R_{A,B},X} and RRA,B,X′R_{R_{A,B},X^{\prime}}, respectively. The top and the bottom are ⊗RA,B,f\otimes_{R_{A,B},f} and ⊗f,RA,B\otimes_{f,R_{A,B}}, respectively. The left and the right side are the 2-morphisms corresponding to the pseudonatural transformations in the tensor product of the objects AA and BB, (RA⊗RB)f(R_{A}\otimes R_{B})_{f} and (RB⊗RA)f(R_{B}\otimes R_{A})_{f}, respectively.

The top triangular prism commutes by (∙⊗(∙⊗→))(\bullet\otimes(\bullet\otimes{\to})). The bottom triangular prism commutes by (∙⊗(→⊗∙))(\bullet\otimes({\to}\otimes\bullet)). The cube in the middle commutes by (∙⊗(∙⊗→))′(\bullet\otimes(\bullet\otimes{\to}))^{\prime}, which is a consequence of (∙⊗⇓)(\bullet\otimes{\Downarrow}) and (∙⊗→→)(\bullet\otimes{\to}\to) as indicated in Lemma 8.

Next, to show that we have really defined a morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}), we have to verify (→⊗(∙⊗∙))({\to}\otimes(\bullet\otimes\bullet)). This means we have to check the commutativity of the following diagram.

A​B​X​Y{\lx@inpgf@ignorespaces ABXY}A​X​Y​B{\lx@inpgf@ignorespaces AXYB}A​X​B​Y{\lx@inpgf@ignorespaces AXBY}    X​Y​A​B{\lx@inpgf@ignorespaces XYAB}X​A​Y​B{\lx@inpgf@ignorespaces XAYB}B​A​X​Y{\lx@inpgf@ignorespaces BAXY}X​A​B​Y{\lx@inpgf@ignorespaces XABY}B​X​Y​A{\lx@inpgf@ignorespaces BXYA}B​X​A​Y{\lx@inpgf@ignorespaces BXAY}X​Y​B​A{\lx@inpgf@ignorespaces XYBA}X​B​Y​A{\lx@inpgf@ignorespaces XBYA}X​B​A​Y{\lx@inpgf@ignorespaces XBAY}A⊗RB,X​Y\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,XY}}RA,B⊗X​Y\scriptstyle{\lx@inpgf@ignorespaces R_{A,B}\otimes XY}⇑A⊗R~(B|X,Y){\lx@inpgf@ignorespaces\Uparrow A\otimes\tilde{R}_{(B|X,Y)}}1.{\lx@inpgf@ignorespaces 1.}RA,X​Y⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,XY}\otimes B}RA,X⊗B​Y\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes BY}⇑⊗RA,X,RB,Y−1{\lx@inpgf@ignorespaces\Uparrow\otimes_{R_{A,X},R_{B,Y}}^{-1}}X​Y⊗RA,B\scriptstyle{\lx@inpgf@ignorespaces XY\otimes R_{A,B}}⇑R~(A|X,Y)⊗B{\lx@inpgf@ignorespaces\Uparrow\tilde{R}_{(A|X,Y)}\otimes B}2.{\lx@inpgf@ignorespaces 2.}B⊗RA,X⊗Y\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{A,X}\otimes Y}X​A⊗RB,Y\scriptstyle{\lx@inpgf@ignorespaces XA\otimes R_{B,Y}}RB,X⊗A​Y\scriptstyle{\lx@inpgf@ignorespaces R_{B,X}\otimes AY}3.{\lx@inpgf@ignorespaces 3.}X⊗RB,Y⊗A\scriptstyle{\lx@inpgf@ignorespaces X\otimes R_{B,Y}\otimes A}X​B⊗RA,Y\scriptstyle{\lx@inpgf@ignorespaces XB\otimes R_{A,Y}}
1.=RRA,B,X⊗Y2.=X⊗RRA,B,Y3.=ROPENRA,B,X⊗Y)1.\>=\>R_{R_{A,B},X}\otimes Y\qquad 2.\>=\>X\otimes R_{R_{A,B},Y}\qquad 3.\>=\>R_{R_{A,B},X\otimes Y)}

As shown in the diagram below, we decompose this diagram in the following way: 1) Three tetrahedra of the form (∙⊗(∙⊗∙⊗∙))(\bullet\otimes(\bullet\otimes\bullet\otimes\bullet)). 2) One prism of the form (∙⊗(∙⊗→))(\bullet\otimes(\bullet\otimes{\to})), namely (A⊗(X⊗(B​Y→Y​B)))(A\otimes(X\otimes(BY\to YB))) (second row, right). 3) One prism of the form (∙⊗(→⊗∙))(\bullet\otimes({\to}\otimes\bullet)), namely (A⊗((B​X→X​B)⊗Y))(A\otimes((BX\to XB)\otimes Y)) (second row, left). 4) One prism of the form (∙⊗⇓)(\bullet\otimes{\Downarrow}), namely (A⊗R~(B|X,Y))(A\otimes\tilde{R}_{(B|X,Y)}) (in the middle of the first row). All of these diagrams commute by our assumptions.

A​B​X​YABXYB​A​X​YBAXYB​X​A​YBXAYB​X​Y​ABXYAA​B​X​YABXYA​X​Y​BAXYBA​X​B​YAXBYB​X​Y​ABXYAX​Y​B​AXYBAX​B​Y​AXBYAA​X​Y​BAXYBX​Y​A​BXYABX​A​Y​BXAYBX​Y​B​AXYBAA​B​X​YABXYA​X​B​YAXBYB​X​A​YBXAYB​X​Y​ABXYAX​B​A​YXBAYX​B​Y​AXBYAA​X​B​YAXBYX​A​B​YXABYX​B​A​YXBAYX​B​Y​AXBYAA​X​B​YAXBYA​X​Y​BAXYBX​A​B​YXABYX​A​Y​BXAYBX​B​Y​AXBYAX​Y​B​AXYBA

(→⊗∙)({\to}\otimes\bullet): For any 1-morphism (f,Rf,−):(A,RA,R~A)→(A′,RA′,R~A′)(f,R_{f,-})\colon(A,R_{A},\tilde{R}_{A})\to(A^{\prime},R_{A^{\prime}},\tilde{R}_{A^{\prime}}) and any object (B,RB,R~B)∈𝒵⁡(𝒞)(B,R_{B},\tilde{R}_{B})\in\mathcal{Z}(\mathcal{C}) we have a 2-isomorphism

Rf,B:(f⊗B)​RA′,B⇒RA,B​(B⊗f)R_{f,B}:(f\otimes B)R_{A^{\prime},B}\Rightarrow R_{A,B}(B\otimes f)

The following diagram shows that Rf,BR_{f,B} satisfies (⇓⊗∙)({\Downarrow}\otimes\bullet) and is therefore a 2-morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}).

A​B​X{\lx@inpgf@ignorespaces ABX}A′​B​X{\lx@inpgf@ignorespaces A^{\prime}BX}B​A​X{\lx@inpgf@ignorespaces BAX}B​A′​X{\lx@inpgf@ignorespaces BA^{\prime}X}(→⊗(∙⊗∙)){\lx@inpgf@ignorespaces({\to}\otimes(\bullet\otimes\bullet))}A​X​B{\lx@inpgf@ignorespaces AXB}A′​X​B{\lx@inpgf@ignorespaces A^{\prime}XB}B​X​A{\lx@inpgf@ignorespaces BXA}B​X​A′{\lx@inpgf@ignorespaces BXA^{\prime}}(→⊗→){\lx@inpgf@ignorespaces({\to}\otimes{\to})}X​A​B{\lx@inpgf@ignorespaces XAB}X​A′​B{\lx@inpgf@ignorespaces XA^{\prime}B}X​B​A{\lx@inpgf@ignorespaces XBA}X​B​A′{\lx@inpgf@ignorespaces XBA^{\prime}}(→⊗(∙⊗∙)){\lx@inpgf@ignorespaces({\to}\otimes(\bullet\otimes\bullet))}f⊗B​X\scriptstyle{\lx@inpgf@ignorespaces f\otimes BX}A⊗RB,X\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,X}}⇓Rf,B⊗X{\lx@inpgf@ignorespaces\Downarrow R_{f,B}\otimes X}RA′,B⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A^{\prime},B}\otimes X}B⊗f⊗X\scriptstyle{\lx@inpgf@ignorespaces B\otimes f\otimes X}B⊗RA′,X\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{A^{\prime},X}}RA,X⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes B}RB,X⊗A′\scriptstyle{\lx@inpgf@ignorespaces R_{B,X}\otimes A^{\prime}}X⊗RA,B\scriptstyle{\lx@inpgf@ignorespaces X\otimes R_{A,B}}X​B⊗f\scriptstyle{\lx@inpgf@ignorespaces XB\otimes f}⇓X⊗Rf,B{\lx@inpgf@ignorespaces\Downarrow X\otimes R_{f,B}}

The left and right sides are the 2-morphisms RRA,B,XR_{R_{A,B},X} and RRA′,B,XR_{R_{A^{\prime},B},X}, respectively. The front and the back sides are pastings as in our treatment in Section 3.2 of the tensor product of an object and a morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}).

We decompose this cube into two commutative triangular prisms of the form (→⊗(∙⊗∙))({\to}\otimes(\bullet\otimes\bullet)), correspoding to (f⊗(B⊗X))(f\otimes(B\otimes X)) and (f⊗(X⊗B))(f\otimes(X\otimes B)), and one cube of the form (→⊗→)({\to}\otimes{\to}), namely (A→A′⊗B​X→X​B)(A\to A^{\prime}\otimes BX\to XB).

(∙⊗→)(\bullet\otimes{\to}): For any 1-morphism (g,Rg,−):(B,RB,R~B)→(B′,RB′,R~B′)(g,R_{g,-}):(B,R_{B},\tilde{R}_{B})\to(B^{\prime},R_{B^{\prime}},\tilde{R}_{B^{\prime}}) and any object (A,RA,R~A)∈𝒵⁡(𝒞)(A,R_{A},\tilde{R}_{A})\in\mathcal{Z}(\mathcal{C}), we have a 2-iso

RA,g:(A⊗g)​RA,B′⇒RA,B​(g⊗A)R_{A,g}:(A\otimes g)R_{A,B^{\prime}}\Rightarrow R_{A,B}(g\otimes A)

The following diagram shows that RA,gR_{A,g} satisfies (⇓⊗∙)({\Downarrow}\otimes\bullet) and is thus a 2-morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}).

A​B​X{\lx@inpgf@ignorespaces ABX}A​B′​X{\lx@inpgf@ignorespaces AB^{\prime}X}B​A​X{\lx@inpgf@ignorespaces BAX}B′​A​X{\lx@inpgf@ignorespaces B^{\prime}AX}(∙⊗(→⊗∙)){\lx@inpgf@ignorespaces(\bullet\otimes({\to}\otimes\bullet))}A​X​B{\lx@inpgf@ignorespaces AXB}A​X​B′{\lx@inpgf@ignorespaces AXB^{\prime}}B​X​A{\lx@inpgf@ignorespaces BXA}B′​X​A{\lx@inpgf@ignorespaces B^{\prime}XA}(∙⊗(→⊗∙)′){\lx@inpgf@ignorespaces(\bullet\otimes({\to}\otimes\bullet)^{\prime})}X​A​B{\lx@inpgf@ignorespaces XAB}X​A​B′{\lx@inpgf@ignorespaces XAB^{\prime}}X​B​A{\lx@inpgf@ignorespaces XBA}X​B′​A{\lx@inpgf@ignorespaces XB^{\prime}A}(∙⊗(→⊗∙)){\lx@inpgf@ignorespaces(\bullet\otimes({\to}\otimes\bullet))}A⊗g⊗X\scriptstyle{\lx@inpgf@ignorespaces A\otimes g\otimes X}A⊗RB,X\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,X}}⇓RA,g⊗X{\lx@inpgf@ignorespaces\Downarrow R_{A,g}\otimes X}RA,B′⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A,B^{\prime}}\otimes X}g⊗A​X\scriptstyle{\lx@inpgf@ignorespaces g\otimes AX}B′⊗RA,X\scriptstyle{\lx@inpgf@ignorespaces B^{\prime}\otimes R_{A,X}}RA,X⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes B}RB′,X⊗A\scriptstyle{\lx@inpgf@ignorespaces R_{B^{\prime},X}\otimes A}X​RA,B\scriptstyle{\lx@inpgf@ignorespaces XR_{A,B}}X⊗g⊗A\scriptstyle{\lx@inpgf@ignorespaces X\otimes g\otimes A}⇓X⊗RA,g{\lx@inpgf@ignorespaces\Downarrow X\otimes R_{A,g}}

The decomposition is similar to the one before.

((∙⊗∙)⊗∙)((\bullet\otimes\bullet)\otimes\bullet): For any objects (A,RA,R~A),(B,RB,R~B),(C,RC,R~C)∈𝒵⁡(𝒞)(A,R_{A},\tilde{R}_{A}),(B,R_{B},\tilde{R}_{B}),(C,R_{C},\tilde{R}_{C})\in\mathcal{Z}(\mathcal{C}) we have the 2-isomorphism R~(A,B|C):=1(RA⊗RB)C\tilde{R}_{(A,B|C)}:=1_{(R_{A}\otimes R_{B})_{C}}:

A⊗B⊗C{\lx@inpgf@ignorespaces A\otimes B\otimes C} C⊗A⊗B{\lx@inpgf@ignorespaces C\otimes A\otimes B}A⊗C⊗B{\lx@inpgf@ignorespaces A\otimes C\otimes B}(RA⊗RB)C\scriptstyle{\lx@inpgf@ignorespaces(R_{A}\otimes R_{B})_{C}}A⊗RB,C\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,C}}⇑1{\lx@inpgf@ignorespaces\Uparrow 1}RA,C⊗B\scriptstyle{\lx@inpgf@ignorespaces R_{A,C}\otimes B}

((∙⊗(∙⊗∙))((\bullet\otimes(\bullet\otimes\bullet)): For any objects (A,RA,R~A),(B,RB,R~B),(C,RC,R~C)∈𝒵⁡(𝒞)(A,R_{A},\tilde{R}_{A}),(B,R_{B},\tilde{R}_{B}),(C,R_{C},\tilde{R}_{C})\in\mathcal{Z}(\mathcal{C}) we have the 2-isomorphism R~(A|B,C)\tilde{R}_{(A|B,C)}:

A⊗B⊗C{\lx@inpgf@ignorespaces A\otimes B\otimes C} B⊗C⊗A{\lx@inpgf@ignorespaces B\otimes C\otimes A}B⊗A⊗C{\lx@inpgf@ignorespaces B\otimes A\otimes C}RA,(B⊗C)\scriptstyle{\lx@inpgf@ignorespaces R_{A,(B\otimes C)}}RA,B⊗C\scriptstyle{\lx@inpgf@ignorespaces R_{A,B}\otimes C}⇑R~(A|B,C){\lx@inpgf@ignorespaces\Uparrow\tilde{R}_{(A|B,C)}}B⊗RA,C\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{A,C}}

To verify that R~(A|−,−)\tilde{R}_{(A|-,-)} is a 2-morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}), we have to check (⇓⊗∙)({\Downarrow}\otimes\bullet). The next diagram gives the proof.

A​B​C​X{\lx@inpgf@ignorespaces ABCX}B​C​A​X{\lx@inpgf@ignorespaces BCAX}B​A​C​X{\lx@inpgf@ignorespaces BACX}(∙⊗(∙⊗∙⊗∙)){\lx@inpgf@ignorespaces(\bullet\otimes(\bullet\otimes\bullet\otimes\bullet))}A​B​X​C{\lx@inpgf@ignorespaces ABXC}B​C​X​A{\lx@inpgf@ignorespaces BCXA}B​A​X​C{\lx@inpgf@ignorespaces BAXC}(∙⊗(∙⊗→)=(A⊗(B⊗(CX→XC))){\lx@inpgf@ignorespaces(\bullet\otimes(\bullet\otimes{\to})=(A\otimes(B\otimes(CX\to XC)))}A​X​B​C{\lx@inpgf@ignorespaces AXBC}B​X​C​A{\lx@inpgf@ignorespaces BXCA}(∙⊗(∙⊗∙⊗∙)){\lx@inpgf@ignorespaces(\bullet\otimes(\bullet\otimes\bullet\otimes\bullet))}B​X​A​C{\lx@inpgf@ignorespaces BXAC}(∙⊗(→⊗∙))=(A⊗(BX→XB)⊗C){\lx@inpgf@ignorespaces(\bullet\otimes({\to}\otimes\bullet))=(A\otimes(BX\to XB)\otimes C)}X​A​B​C{\lx@inpgf@ignorespaces XABC}X​B​C​A{\lx@inpgf@ignorespaces XBCA}(∙⊗(∙⊗∙⊗∙)){\lx@inpgf@ignorespaces(\bullet\otimes(\bullet\otimes\bullet\otimes\bullet))}X​B​A​C{\lx@inpgf@ignorespaces XBAC}RA,B​C⊗X\scriptstyle{\lx@inpgf@ignorespaces R_{A,BC}\otimes X}A​B⊗RC,X\scriptstyle{\lx@inpgf@ignorespaces AB\otimes R_{C,X}}B​C⊗RA,X\scriptstyle{\lx@inpgf@ignorespaces BC\otimes R_{A,X}}A⊗RB,X⊗C\scriptstyle{\lx@inpgf@ignorespaces A\otimes R_{B,X}\otimes C}B⊗RC,X⊗A\scriptstyle{\lx@inpgf@ignorespaces B\otimes R_{C,X}\otimes A}RA,X⊗B​C\scriptstyle{\lx@inpgf@ignorespaces R_{A,X}\otimes BC}RB,X⊗C​A\scriptstyle{\lx@inpgf@ignorespaces R_{B,X}\otimes CA}

The top triangle corresponds to the 2-morphism R~(A|B,C)⊗X\tilde{R}_{(A|B,C)}\otimes X. The bottom triangle corresponds to the 2-morphism X⊗R~(A|B,C)X\otimes\tilde{R}_{(A|B,C)}. The back side is RRA,B⊗C,XR_{R_{A,B\otimes C},X}, the left front side is RRA,B⊗C,XR_{R_{A,B}\otimes C,X} and the right front side is RB⊗RA,C,XR_{B\otimes R_{A,C},X}. The decomposition is indicated in the diagram.

Now we have to verify that these data satisfy all the axioms of a braided monoidal 2-category. The tetrahedron (∙⊗(∙⊗∙⊗∙))(\bullet\otimes(\bullet\otimes\bullet\otimes\bullet)) commutes by the definition of the objects of 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}). The diagram ((∙⊗∙)⊗(∙⊗∙))((\bullet\otimes\bullet)\otimes(\bullet\otimes\bullet)) commutes by the definition of the tensor product of two objects in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}). By the same definition can be shown that ((∙⊗∙⊗∙)⊗∙)((\bullet\otimes\bullet\otimes\bullet)\otimes\bullet) commutes in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}). Note that because of our special choice of the 2-morphism RRA,B,−R_{R_{A,B},-} that completes the morphism RA,BR_{A,B} to a morphism in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}), the two 2-morphisms S+S^{+} and S−S^{-} are equal in 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}).

The other axioms of a braided monoidal 2-category are either part of our definitions, or else we have indicated within our Remarks which definitions imply them. We may summarize by stating:

0N8D

Theorem 15. Given any semistrict monoidal category 𝒞\mathcal{C}, the center 𝒵⁡(𝒞)\mathcal{Z}(\mathcal{C}) is semistrict braided monoidal 2-category.

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.

John C. Baez, Martin Neuchl

Original source: arXiv:q-alg/9511013v2